x^2+1+4x-5=8

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Solution for x^2+1+4x-5=8 equation:


Simplifying
x2 + 1 + 4x + -5 = 8

Reorder the terms:
1 + -5 + 4x + x2 = 8

Combine like terms: 1 + -5 = -4
-4 + 4x + x2 = 8

Solving
-4 + 4x + x2 = 8

Solving for variable 'x'.

Reorder the terms:
-4 + -8 + 4x + x2 = 8 + -8

Combine like terms: -4 + -8 = -12
-12 + 4x + x2 = 8 + -8

Combine like terms: 8 + -8 = 0
-12 + 4x + x2 = 0

Factor a trinomial.
(-6 + -1x)(2 + -1x) = 0

Subproblem 1

Set the factor '(-6 + -1x)' equal to zero and attempt to solve: Simplifying -6 + -1x = 0 Solving -6 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '6' to each side of the equation. -6 + 6 + -1x = 0 + 6 Combine like terms: -6 + 6 = 0 0 + -1x = 0 + 6 -1x = 0 + 6 Combine like terms: 0 + 6 = 6 -1x = 6 Divide each side by '-1'. x = -6 Simplifying x = -6

Subproblem 2

Set the factor '(2 + -1x)' equal to zero and attempt to solve: Simplifying 2 + -1x = 0 Solving 2 + -1x = 0 Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -1x = 0 + -2 Combine like terms: 2 + -2 = 0 0 + -1x = 0 + -2 -1x = 0 + -2 Combine like terms: 0 + -2 = -2 -1x = -2 Divide each side by '-1'. x = 2 Simplifying x = 2

Solution

x = {-6, 2}

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